,
p = progressão.

f [p] = f [px+ √(x²) /pP -logx] {+,*,/, -} [+] f1 [p+ √(x²)+logy] [p+LOGy/pP -x] {+,*,/, -} [+] f2 [p+ √(x²)LOGw] [p+ √(x²)+LOGw/pP -x] [n] ............

,

xp

${\textstyle f(x)}$ Σ a ${\textstyle n}$ [x+ √(x²)-p+LOGX] sendo an = f[p √(x²)+LOGY/pP -x]

i =n =0

,
p = progressão.

f [p] = f [ √(x²)+px/pP -x] {+,*,/, -} [+] f1 [ √(x²)+py] [py/pP -x] {+,*,/, -} [+] f2 [ √(x²)+pw] [pw/pP -x] [n]

,

xp

${\textstyle f(x)}$ Σ a ${\textstyle n}$ [x √(x²)-p] sendo an = f[ √(x²)+p/pP -x]

i =n =0

,
p = progressão.

f [p] = f [px/pP -logx] {+,*,/, -} [+] f1 [p+logy] [p+LOGy/pP -x] {+,*,/, -} [+] f2 [p+LOGw] [p+LOGw/pP -x] [n] ............

,

xp

${\textstyle f(x)}$ Σ a ${\textstyle n}$ [x-p+LOGX] sendo an = f[p+LOGY/pP -x]

i =n =0

,
p = progressão.

f [p] = f [px/pP -x] {+,*,/, -} [+] f1 [py] [py/pP -x] {+,*,/, -} [+] f2 [pw] [pw/pP -x] [n]

,

xp

${\textstyle f(x)}$ Σ a ${\textstyle n}$ [x-p] sendo an = f[p/pP -x]

i =n =0

Graceli series theory. pure mathematics.

terça-feira, 20 de setembro de 2016

${\textstyle f(x)}$ Σ a ${\textstyle n}$ [x+ √(x²)-p+LOGX] sendo an = f[p √(x²)+LOGY/pP -x]

${\textstyle f(x)}$ Σ a ${\textstyle n}$ [x √(x²)-p] sendo an = f[ √(x²)+p/pP -x]

${\textstyle f(x)}$ Σ a ${\textstyle n}$ [x-p+LOGX] sendo an = f[p+LOGY/pP -x]

${\textstyle f(x)}$ Σ a ${\textstyle n}$ [x-p] sendo an = f[p/pP -x]

terça-feira, 20 de setembro de 2016

Σ a [x+ √(x²)-p+LOGX] sendo an = f[p √(x²)+LOGY/pP -x]

Σ a [x √(x²)-p] sendo an = f[ √(x²)+p/pP -x]

Σ a [x-p+LOGX] sendo an = f[p+LOGY/pP -x]

Σ a [x-p] sendo an = f[p/pP -x]

${\textstyle f(x)}$ Σ a ${\textstyle n}$ [x+ √(x²)-p+LOGX] sendo an = f[p √(x²)+LOGY/pP -x]

${\textstyle f(x)}$ Σ a ${\textstyle n}$ [x √(x²)-p] sendo an = f[ √(x²)+p/pP -x]

${\textstyle f(x)}$ Σ a ${\textstyle n}$ [x-p+LOGX] sendo an = f[p+LOGY/pP -x]

${\textstyle f(x)}$ Σ a ${\textstyle n}$ [x-p] sendo an = f[p/pP -x]